How do you find the limit of (3x + 9)/(x^2 - 9)3x+9x2−9 as x approaches -3?
2 Answers
Jul 8, 2018
Explanation:
Given:
First factor both the numerator and denominator. Note that the denominator is the difference of squares,
Now take the limit at
Jul 8, 2018
Explanation:
=lim_(xto-3)(3cancel((x+3)))/(cancel((x+3))(x-3))
=lim_(xto-3)3/(x-3)=3/(-6)=-1/2