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How do you find the limit #lim (pi^x-pi)/(pi^(2x)-pi^2)# as #x->1#?

1 Answer

Feb 1, 2017

#1/(2pi)#

Explanation:

#lim_(x->1) (pi^x-pi)/(pi^(2x)-pi^2)=lim_(x->1) (pi^x-pi)/((pi^(x)-pi)(pi^(x)+pi))=1/(2pi)#

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