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How do you find the limit #lim (3^(x+1)-2^(x+4))/(3^(x-2)+2^(x-1)+6)# as #x->oo#?

1 Answer

Oct 18, 2017

#3#

Explanation:

#lim_(x->oo) (3^(x+1)-2^(x+4))/(3^(x-2)+2^(x-1)+6) = lim_(x->oo)(3^-1-2^4*(2/3)^x)/(3^-2+2^-1(2/3)^x+6/3^x) = 3#

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