How do you find the limit #lim 3^t-2^t# as #t->oo#?

1 Answer
1s2s2p
Oct 13, 2017

There is no limit as #t->oo#, the equation will continue to approach #oo# as #t->oo#

Explanation:

Not much maths is involved in this.

You know that you are taking one exponential growth from another. However, the smaller one is being taken away from the bigger one. Also, the gap between #3^t# and #2^t# will continue to get greater and greater.

The equation would plot the value for this gap against #t#, and as one is growing faster than the other, the line will move further and further away from 0.

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