How do you find the length of side c for the triangle with dimensions A = 57° , a = 11, b = 10?

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Answer 1 · 2015-09-12T13:15:19

Find Angle B, then, with A and B we can find angle C. Knowing C will allow us to find c.

$sinB = 10/11 sin57^@$

So $B ~~ 49.7^@$

$C = 180^@ -A - B ~~ 73.3^@$

$c = 11/(sin57^@) sin73.3^@ ~~ 12.6$

Answer 2 · 2015-09-12T13:51:24

It is $c=10,059$

$c^2=a^2+b^2-2abcosA=>c^2=(11)^2+(10)^2-2*10*11*cos(57)=> c=10,059$