How do you find the Least common multiple of $20 y, 14 y^{2}$ $20y, 14y^2$ ?

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Answer 1 · 2016-11-30T15:20:48

$L C M = 2^{2} \cdot 5 \cdot 7 \cdot y^{2} = 140 y^{2}$ $LCM = 2^2*5*7*y^2=140y^2$

Factorize the two expressions:

$20 y = 2^{2} \cdot 5 \cdot y$ $20y=2^2*5*y$
$14 y^{2} = 2 \cdot 7 \cdot y^{2}$ $14y^2=2*7*y^2$

The LCM is the product of all factors - common or not common - taken once with the highest exponent.

$L C M = 2^{2} \cdot 5 \cdot 7 \cdot y^{2} = 140 y^{2}$ $LCM = 2^2*5*7*y^2=140y^2$

How do you find the Least common multiple of 20y,14y220y, 14y^2?