How do you find the LCM for 3, 4w+2 and 4w^2-1?

1 Answer
Jun 8, 2015

One way is to factor each of them completely, then multiply the non-duplicated factors together. I say non-duplicated, but if a factor is repeated in one of the factorisations of the starting expressions, then it has to occur at least that many times in the LCM.

Anyway:

3 is completely factored already.
4w+2 = 2(2w+1)
4w^2-1 = (2w+1)(2w-1)

So the unique factors are: 3, 2, (2w+1) and (2w-1).

None of these factors occurs in one of the original expressions with a multiplicity greater than 1, so we can just multiply them together to get the LCM:

3*2*(2w+1)(2w-1) = 6*(4w^2-1) = 24w^2-6