How do you find the inverse of #y=x^3 +5#?

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Answer 1 · 2016-01-04T00:48:28

Reformulate the equation with #x# isolated on one side to find inverse function:

#f^(-1)(y) = root(3)(y-5)#

Let #f(x) = x^3+5#

Let #y = f(x) = x^3+5#

Subtract #5# from both ends to get:

#y - 5 = x^3#

Take the cube root of both sides and transpose to get:

#x = root(3)(y - 5)#

Hence:

#f^(-1)(y) = root(3)(y-5)#