How do you find the inverse of #y=log_2 2x# and is it a function?

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Answer 1 · 2016-10-21T18:46:46

#y = log_2(2x)#

We obtain the inverse by switching the x and y values within the function.

#x= log_2(2y)#

#2^x = 2y#

#y= 1/2(2^x)#

#f^-1(x) = 1/2(2^x)#

Hopefully this helps!