How do you find the inverse of $y = 2^(3 - x)$ and is it a function?

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Answer 1 · 2016-05-30T06:42:44

The inverse function is $3-x= log_2y$ , and so, $x= 3-log_2 y=3-log y/log 2$

Use the inversion formula X = log_-b y $,, if y=b^X$ and

$log_b a = log_c a/log_c b$ , with c at your choice.

Here, the inverse is $3-x=log_2 y=log y/log 2$ .

So, $x = 3- log y/log 2$ .-, .

How do you find the inverse of y = 2^(3 - x)y = 2^(3 - x) and is it a function?