How do you find the inverse of #log 2^-x#?

1 Answer
Karthik G
Dec 24, 2015

Step by Step process is given below.

Explanation:

#y=log(2^(-x))#

Note (x,y) inverse is (y,x) to get the inverse function we need to do the following steps.

#1.# swap #x # and # y#
#x=log(2^(-y))#

#2.# solve for #y#

#x=-y*log(2)# using #log(a^n) = nlog(a)#
#-x=log(2)y#
#-x/log(2) =y#

The inverse function is #f^-1(x) = -x/log(2)#

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