How do you find the inverse of #ln(x^2)# and is it a function?
1 Answer
Mar 28, 2016
If
#e^y = x^2#
#x = +- sqrt{e^y}#
It is not a function, as given a value for
If
#e^y = x^2#
#x = +- sqrt{e^y}#
It is not a function, as given a value for