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How do you find the inverse of #f(x) = x^3 + 5#?

1 Answer

Aug 11, 2015

#f^-1 (x) =root(3)(x-5)#

Explanation:

let y= #x^3 +5#

Interchange y and x and then solve for y as follows:

x= #y^3 +5#

#y^3= x-5

y= #f^-1 (x) =root(3)(x-5)#

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