How do you find the inverse of $f(x)=x^2 - 1$ ?

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Answer 1 · 2015-09-27T12:57:01

Find the inverse by swapping x and y, then solve for y.

$y = x^2-1$

Now, swap x and y:

$x = y^2-1$

Finally, solve for y:

$y = +- sqrt(x+1)$

So, the inverse is:

$f^-1(x) = +- sqrt(x+1)$

hope that helps!

How do you find the inverse of f(x)=x^2 - 1f(x)=x^2 - 1?