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How do you find the inverse of #f(x)=(x+1)^2#?

1 Answer

Sep 29, 2015

The inverse function is #f(y)=sqrt(y)-1#

Explanation:

To find some (simple) inverse functions, you can write the espression as #y=f(x)#, and then try to isolate #x#. In this case, it is possible:

#y=(x+1)^2#

#sqrt(y)=x+1# (#sqrt(y)# makes sense because #y=(x+1)^2#, so it's positive)

#sqrt(y)-1=x#

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