How do you find the inverse of $F (x) = (\frac{7}{x}) - 3$ $F(x) = (7/x) - 3$ ?

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Answer 1 · 2015-10-24T15:37:36

$\frac{7}{x + 3}$ $7/(x+3)$

For finding the inverse write $F (x) = y = \frac{7}{x} - 3$ $F(x)=y= 7/x -3$

Now interchange x and y, $x = \frac{7}{y} - 3$ $x= 7/y-3$ and solve for y.

$y = \frac{7}{x + 3}$ $y= 7/(x+3)$ . That is the required inverse.

How do you find the inverse of F(x) = (7/x) - 3 F(x)=(7x)−3F(x) = (7/x) - 3 ?