How do you find the inverse of #f(x) = 3x + 1# and is it a function?

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Answer 1 · 2016-03-22T00:13:47

See explanation...

Let #y = f(x) = 3x+1#

Subtract #1# from both ends to get:

#y - 1 = 3x#

Divide both sides by #3# and transpose to get:

#x = (y-1)/3#

Having expressed #x# in terms of #y#, we can deduce that:

#f^(-1)(y) = (y-1)/3#

Since #f^(-1)(y)# is uniquely defined for any #y in RR#, it is a function.