How do you find the inverse of $f(x)=3x+1$ ?

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Answer 1 · 2018-06-07T20:16:45

$f^-1(x)=(x-1)/3$

Let's start by replacing $f(x)$ with $y$ . We now have

$y=3x+1$

Let's switch $x$ and $y$ to get

$x=3y+1$

Let's solve for $y$ now. We can start by subtracting $1$ from both sides to get

$3y=x-1$

Dividing both sides by $3$ , we get

$y=(x-1)/3$

This is our inverse, so we can replace $y$ with $f^-1(x)$ :

$f^-1(x)=(x-1)/3$

Hope this helps!

Answer 2 · 2018-06-07T20:18:43

$f^-1(x)=1/3(x-1)$

$"let "y=3x+1$

$"rearrange making x the subject"$

$3x=y-1$

$x=1/3(y-1)$

$rArrf^-1(x)=1/3(x-1)$

How do you find the inverse of f(x)=3x+1f(x)=3x+1?