How do you find the inverse of $f (x) = 3 x + 1$ $f(x) = 3x + 1$ ?

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Answer 1 · 2015-11-11T23:08:46

$f^{- 1} (x) = \frac{x - 1}{3}$ $f^(-1)(x)=(x-1)/3$

By definition, the inverse function is defined as follows :

$y = f^{- 1} (x) \Leftrightarrow f (y) = x$ $y=f^(-1)(x)iff f(y)=x$

So in this case it would be so $\Leftrightarrow 3 y + 1 = x$ $iff 3y+1=x$

$\Leftrightarrow y = \frac{x - 1}{3}$ $iffy=(x-1)/3$

How do you find the inverse of f(x) = 3x + 1f(x)=3x+1f(x) = 3x + 1?