How do you find the inverse of #A=##((6, 3), (4, 6))#?
1 Answer
Feb 15, 2016
#((1/4,-1/8),(-1/6,1/4))#
Explanation:
For any matrix
#A =((a,b),(c,d))# then the inverse matrix is found as follows:
# A^-1 = 1/(ad-bc)((d,-b),(-c,a))# ad - bc , is called the 'determinant ,and it's value determines whether an inverse matrix exists or not.
If tdet(A) = 0 ,then inverse does not exist and matrix is said to be singular.
using the values from the question :
ad - bc =
#(6xx6) - (3 xx4) = "24 , hence matrix exists"#
#1/24((6,-3),(-4,6)) = ((1/4,-1/8),(-1/6,1/4))#
