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How do you find the inverse of #A=##((18, -3), (-3, 15))#?

1 Answer

Konstantinos Michailidis

Feb 21, 2016

To find the inverse #A^-1#of a matrix #A# which is #2x2# the formula is

#[((a, b), (c, d))]^(-1)=1/[a*d-b*c]*[((d, -b), (-c, a))]#

Just replace for #a=18,b=-3,c=-3,d=15# to get

#A^-1=1/87*((5,1),(1,6))#

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