How do you find the integration of : ((1-1/x) cos(x-Inx))dx?

1 Answer
Apr 29, 2018

sin(x-ln x)+C

Explanation:

Substitute x-ln x= u. Then we have (1-1/x)dx=du and so

int (1-1/x)cos(x-ln x)dx = int cos u du
= sin u+C = sin(x-ln x) + C