How do you find the integral of #18e^(3t) dt #?
1 Answer
Sep 4, 2015
Explanation:
From laws of integration, the integral of e^t is e^t.
We may substitute u = 3t, which means du = 3 dt and rewrite this integral as
18/3
This then becomes 6 e^u + C,where C is the constant of integration.
Substituting back we get the answer as 6e^(3t) + C
