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How do you find the integral #int 3t^2(t^3+4)^5 dt# using substitution?

1 Answer

Feb 8, 2017

#1/6(t^3+4)^6+C.#

Explanation:

Take #t^3+4=x rArr 3t^2dt=dx#

#:. I=int(t^3+4)^5(3t^2)dt#

#=intx^5dx=x^6/6=1/6(t^3+4)^6+C.#

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