How do you find the greatest common factor of $80 x^{3}, 30 y x^{2}$ $80x^3, 30yx^2$ ?

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Answer 1 · 2018-03-10T22:24:56

$g c f = 10 x^{2}$ $gcf=10x^2$

Find the prime factorization of each of the given numbers:

$80 x^{3} = 16 \cdot 5 = 2^{4} \cdot 5 \cdot x^{3}$ $80x^3=16*5=2^4*5*x^3$
$30 y x^{2} = 2 \cdot 3 \cdot 5 \cdot y \cdot x^{2}$ $30yx^2=2*3*5*y*x^2$

the greatest common factor is the product of all common factors taken one at a time at the lowest exponent:

$g c f = 2 \cdot 5 \cdot x^{2} = 10 x^{2}$ $gcf=2*5*x^2=10x^2$

How do you find the greatest common factor of 80x^3, 30yx^280x3,30yx280x^3, 30yx^2?