How do you find the general form of the line with x intercept of -4, y intercept of 5?

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Answer 1 · 2016-07-02T14:05:25

Point-slope form #y -0 = -5/4 (x +4)#

Standard form #4y+5x+20=0#

To find the equation of the line for a line with an x intercept of #-4# and a y intercept of #5#, we can begin with the points of interception.

x intercept #=(-4,0)#
y intercept #=(0,5)#

The formula for the slope of a line based upon two coordinate points is

#m = (y_2-y_1)/(x_2-x_1)#

For the coordinate points #(5,7) and (9,14)#
#x_1 = -4#
#x_2 = 0#
#y_1 = 0#
#y_2 = 5#

#m = (5-0)/(0-(-4))#

#m = 5/-4#

The slope is #m = -5/4#

The point slope formula would be written as
#y - y_1 = m( x - x_1)#

#m = -5/4#
#x_1 = -4#
#y_1=0#

#y -0 = =5/4 (x -(-4))#

#y = -5/4x -5#

#(4)y=(4) (-5/4x) -5(4)#

#4y=-5x-20#

#4y+5x+20=0#