# How do you find the general form of the line passing through (-1,2) and (2,5)?

##### 2 Answers

y=x+3

#### Explanation:

First, find the slope. To do this, plug in values for this equation.

m is the slope and the values are your original coords.

Now that we have the slope, we use it to find the y-intercept, and the slope-intercept form.

We use point-slope for this.

The slope is 1, and the y-intercept is 3. The slope-intercept form is "y=x+3", and the point-slope form is "y-2=1(x+1)"

#### Explanation:

#"the equation of a line in "color(blue)"general form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By+C=0)color(white)(2/2)|)))#

where A is a positive integer and B, C are integers.

#"to begin express the equation in "color(blue)"slope-intercept form"#

#• y=mx+b#

#"where m represents the slope and b, the y-intercept"#

#"to calculate m use the "color(blue)"gradient formula"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_2-y_1)/(x_2-x_1))color(white)(2/2)|)))#

where# (x_1,y_1),(x_2,y_2)" are 2 coordinate points"#

#"the points are " (x_1,y_1)=(-1,2),(x_2,y_2)=(2,5)#

#rArrm=(5-2)/(2-(-1))=3/3=1#

#rArry=x+blarr" is the partial equation"#

#"to find b use either of the 2 given points"#

#"using " (2,5)" then"#

#5=2+brArrb=3#

#rArry=x+3larrcolor(red)" in slope-intercept form"#

#rArrx-y+3=0larrcolor(red)" in general form"#