How do you find the GCF of $14n, 42n^3$ ?

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Answer 1 · 2018-03-07T22:57:22

See a solution process below:

Find the prime factors for each term as:

$14n = 2 xx 7 xx n$

$42n^3 = 2 xx 3 xx 7 xx n xx n xx n$

Now identify the common factors and determine the GCF:

$14n = color(red)(2) xx color(red)(7) xx color(red)(n)$

$36 = color(red)(2) xx 3 xx color(red)(7) xx color(red)(n) xx n xx n$

Therefore:

$"GCF" = color(red)(2) xx color(red)(7) xx color(red)(n) = 14n$

How do you find the GCF of 14n, 42n^314n, 42n^3?