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How do you find the formula for #a_n# for the arithmetic sequence #a_1=x, d=2x#?

1 Answer

Shwetank Mauria

Feb 22, 2017

#a_n=(2n-1)x#

Explanation:

#n^(th)# term #a_n# of an arithmetic sequence, whose first term is #a_1# and common difference is #d# is given by

#a_n=a_1+(n-1)d#

Here #a_1=x# and #d=2x#, therefore #a_n# is given by

#a_n=x+(n-1)2x=x+(2n-2)x=(1+2n-2)x=(2n-1)x#

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