How do you find the five remaining trigonometric function satisfying $tantheta=-12/5$ , $sintheta>0$ ?

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How do you find the five remaining trigonometric function satisfying $tantheta=-12/5$ , $sintheta>0$ ?

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Answer 1 · 2017-03-13T04:38:21

cos^2 t = 1/(1 + tan^2 t) = 1/(1 + 144/25) = 25/169
$cos t = +- 5/13$
$sin t = (tan t)(cos t) = (-12/5)(- 5/13) = 12/13$
Note. tan t < 0 and sin t > 0, then, cos t < 0)
$cot t = 1/(tan) = - 5/12$
$sec t = 1/(cos) = - 13/5$
$csc t = 1/(sin) = 13/12$

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How do you find the five remaining trigonometric function satisfying $tantheta=-12/5$ , $sintheta>0$ ?

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How do you find the five remaining trigonometric function satisfying tantheta=-12/5tantheta=-12/5, sintheta>0sintheta>0?

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How do you find the five remaining trigonometric function satisfying $tantheta=-12/5$ , $sintheta>0$ ?