How do you find the first and second derivative of #y=2^-x#?

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How do you find the first and second derivative of #y=2^-x#?

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Answer 1 · 2017-02-17T17:46:02

#f'(x)=-2^(-x)ln2#

Explanation:

The derivative of any function such as #b^x# is #b^xlnb#. Knowing that, we can clearly see b is 2. But since it's a negative x, we must use chain rule and multiply by #-1#

#f(x)=2^(-x)# will become #f'(x)=-2^(-x)ln2#

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How do you find the first and second derivative of #y=2^-x#?

1 Answer

Explanation:

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