How do you find the first and second derivative of #(ln(x))^2#? Calculus Graphing with the Second Derivative Notation for the Second Derivative 1 Answer Konstantinos Michailidis May 23, 2016 The first derivative is #d((lnx)^2)/dx=2*lnx*d(lnx)/dx=2*lnx*1/x# The second derivative is #d(2*lnx/x)/dx=2*[lnx'*x-lnx*x']/[x^2]=2*(1-lnx)/(x^2)# Answer link Related questions What is notation for the Second Derivative? What is Leibniz notation for the second derivative? What is the second derivative of #e^(2x)#? How do you find the first, second derivative for #3x^(2/3)-x^2#? What is the second derivative of #y=x*sqrt(16-x^2)#? How do you find the first and second derivative of #(lnx)/x^2#? How do you find the first and second derivative of #lnx^(1/2)#? How do you find the first and second derivative of #x(lnx)^2#? How do you find the first and second derivative of #ln(x^2-4)#? How do you find the first and second derivative of #ln(lnx^2)#? See all questions in Notation for the Second Derivative Impact of this question 2056 views around the world You can reuse this answer Creative Commons License