How do you find the exact values of the six trigonometric function of theta if the terminal side of theta in the standard position contains the point (sqrt2,-sqrt2)?

1 Answer
Nghi N.
Oct 31, 2016

Find values of trig functions

Explanation:

The point M (sqrt2, -sqrt2) is located at extremity of arc (-pi)/4 Quadrant IV, on the trig circle with diameter R = 2.
(Right triangle formula: R^2 = (sqrt2)^2 + (sqrt2)^2 = 4 --> R = 2)
sin t = -sqrt2/R = - sqrt2/2
cos t = sqrt2/2
tan t = sin/(cos) = - 1
cot t = 1/(tan) = - 1
sec t = 1/(cos) = 2/sqrt2 = sqrt2
csc t = 1/(sin) = - sqrt2

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