How do you find the exact values of the six trig functions of angle 120?

1 Answer
Harish Chandra Rajpoot
Jul 28, 2018

See values of all six trig. functions below

Explanation:

\sin120^\circ=\sin(180^\circ-60^circ)=\sin60^\circ=\sqrt3/2

\cos120^\circ=\cos(180^\circ-60^circ)=-\cos60^\circ=-1/2

\tan120^\circ=\tan(180^\circ-60^circ)=-\tan60^\circ=-\sqrt3

\cosec120^\circ=\cosec(180^\circ-60^circ)=\cosec 60^\circ=2/\sqrt3

\sec120^\circ=\sec(180^\circ-60^circ)=-\sec 60^\circ=-2

\cot120^\circ=\cot(180^\circ-60^circ)=-\cot60^\circ=-1/\sqrt3

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