How do you find the exact value of the six trigonometric functions of the angle whose terminal side passes through $(- 2 x, - 3 x)$ $(-2x, -3x)$ ?

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Answer 1 · 2017-01-13T19:24:21

$r = \sqrt{{(- 2 x)}^{2} + {(- 3 x)}^{2}} = \sqrt{13} x$ $r=sqrt((-2x)^2+(-3x)^2)=sqrt13x$

$sin(θ)=-3/sqrt13$

$csc(θ)=-sqrt13/3$

$cos(θ)=-2/sqrt13$

$sec(θ)=-sqrt13/2$

$tan(θ)=3/2$

$cot(θ)=2/3$

How do you find the exact value of the six trigonometric functions of the angle whose terminal side passes through (-2x, -3x)(−2x,−3x)(-2x, -3x)?