How do you find the exact value of the six trigonometric functions of the angle whose terminal side passes through #(-2x, -3x)#?

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Answer 1 · 2017-01-13T19:24:21

#r=sqrt((-2x)^2+(-3x)^2)=sqrt13x#

#sin(θ)=-3/sqrt13#

#csc(θ)=-sqrt13/3#

#cos(θ)=-2/sqrt13#

#sec(θ)=-sqrt13/2#

#tan(θ)=3/2#

#cot(θ)=2/3#