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How do you find the exact value of #tan pi/3#?

1 Answer

Apr 21, 2015

This is doable without using any complicated identities.

#pi/3# radians #= 60^o#

#tan 60^o = (sin 60^o) / (cos 60^o) = (sqrt(3)/2)/(1/2) = cancel(2)*sqrt(3)/cancel(2) = sqrt(3) ≈ 1.732#

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