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How do you find the exact value of tan (23pi/6)?

1 Answer

Mar 13, 2018

# -1/sqrt3, or, -sqrt3/3#.

Explanation:

#tan(23/6pi)=tan{(24-1)/6pi}=tan{(24/6-1/6)pi}#,

#=tan(4pi-pi/6)#.

Since, #(4pi-pi/6)# lies in the fourth quadrant, where, tan is

-ve, we get,

#tan(23/6pi)=tan(4pi-pi/6)=-tan(pi/6)=-1/sqrt3, or, -sqrt3/3#.

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