How do you find the exact value of $sin ((7pi)/12)$ ?

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Answer 1 · 2016-04-09T07:49:22

$sin(7pi/12)=sin(pi/3+pi/4)$
$=sin(pi/3)cos( pi/4)+cos(pi/3)sin(pi/4)$
$=sqrt3/2xx1/sqrt2+1/2xx1/sqrt2=(sqrt3+1)/(2sqrt2)$

How do you find the exact value of sin ((7pi)/12)sin ((7pi)/12)?