How do you find the exact value of sin 5Pi/4?

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How do you find the exact value of sin 5Pi/4?

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Answer 1 · 2018-04-27T14:27:38

$-sqrt2/2$

Explanation:

$(5pi)/4" is situated in the third quadrant hence"$

$sin((5pi)/4)<0$

$"the "color(blue)"related acute angle is"$

$(5pi)/4-pi=pi/4$

$rArrsin((5pi)/4)=-sin(pi/4)=1/sqrt2=sqrt2/2$

Answer 2 · 2018-04-27T14:27:45

$sin((5pi)/4)=-sqrt2/2$

Explanation:

$sin((5pi)/4)=sin(pi+pi/4)=sinpicos(pi/4)+cospisin(pi/4)=0-sqrt2/2=-sqrt2/2$

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How do you find the exact value of sin 5Pi/4?

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