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How do you find the exact value of #sin (5pi)/3#?

1 Answer

Sep 25, 2015

0 for #sin(5pi)/3# and #-(sqrt3)/2# for #sin((5π)/3)#

Explanation:

#sin(5pi)/3=0/3=0#

as #sin(kpi)=0# for all integer values of k

For #sin((5π)/3)#,

#sin((5π)/3)=sin((6π-π)/3)#
#=sin(2π-π/3)#
#=-sin(π/3)#
#=-sqrt3/2#

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