How do you find the exact value of $sin(-(3pi)/2)$ ?

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Answer 1 · 2017-01-20T13:08:31

See explanation.

$sin(-3/2pi)=-sin(3/2pi)=-(-1)=1$

The first transformation uses the fact that $sinx$ is an odd function (i.e. $sin(-x)=-sinx$ )

How do you find the exact value of sin(-(3pi)/2)sin(-(3pi)/2)?