How do you find the exact value of #csc((17pi)/6)#? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer turksvids Jan 23, 2018 2 Explanation: First find the angle coterminal to #(17pi)/6# that falls between #0# and #2pi#: #(17pi)/6-2pi=(5pi)/6#. So we know that #csc((17pi)/6) = csc((5pi)/6)#. #csc(x)=1/sin(x)# and we know that #sin((5pi)/6) = 1/2# because it's from the Unit Circle. So: #csc((17pi)/6) = csc((5pi)/6) = 1/sin((5pi)/6) = 1/(1/2)=2#. Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 13739 views around the world You can reuse this answer Creative Commons License