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How do you find the exact value of #cot ((7pi)/4)#?

1 Answer

May 30, 2015

On the trig unit circle,

#cot ((7pi)/4) = 1/tan ((7pi)/4)#

#tan ((7pi)/4) = tan (- pi/4 + 2pi)# (same terminal)
#tan (- pi/4 + 2pi) = tan (- pi/4) = - tan (pi/4) = - 1#

#cot ((7pi)/4) = 1/tan = (1/-1) = -1#

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