How do you find the exact value of Cot π/3 - cosπ/6?

1 Answer
Noah G
Jan 4, 2018

This evaluates to -1/sqrt(3)

Explanation:

We can rewrite cotx as cosx/sinx.

=cos(pi/3)/sin(pi/3) - cos(pi/6)

We can now easily evaluate using our knowledge of the 30-60-90 triangle.

= (1/2)/(sqrt(3)/2) - sqrt(3)/2

= 1/sqrt(3) - sqrt(3)/2

= (1 - 3)/(2sqrt(3))

= -1/sqrt(3)

Hopefully this helps!

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