How do you find the exact value of #Cos[sin^-1(1/3) - arcsin(1/2)]#?

Question

How do you find the exact value of #Cos[sin^-1(1/3) - arcsin(1/2)]#?

1 Answer

Impact of this question

2361 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-26T15:00:21

#1/6 + sqrt(2/3)#

Explanation:

First we will consider that #sin^{-1} equiv arcsin#. We will need the identity
#cos(a-b)=cos(a)cos(b)+sin(a)sin(b)# and also that
#cos(arcsin(x))=sqrt(1-x^2)#. With all this in mind
#cos(arcsin(1/3)-arcsin(1/2))=1/6 + sqrt(2/3)#

Science

Math

Humanities

... and beyond

How do you find the exact value of #Cos[sin^-1(1/3) - arcsin(1/2)]#?

1 Answer

Explanation:

Related questions

Impact of this question