How do you find the exact 6 trigonometric ratios for the angle x whose radian measure is $(5pi)/6$ ?

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Answer 1 · 2015-05-05T03:15:04

$sin [(5pi)/6] = sin (pi- pi/6) = sin (pi/6) = 1/2$

$cos [(5pi)/6)] = cos (Pi - Pi/6) = -cos (pi/6) = (-sqr3)/2$

$tan ((5pi)/6) = -1/(sqr3) = -(sqr3)/3$

$cot [(5pi)/6] = -sqr3$

$sec [(5pi)/6] = 2$

$csc [(5pi)/6] = -2/(sqr3)$

How do you find the exact 6 trigonometric ratios for the angle x whose radian measure is (5pi)/6(5pi)/6?