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How do you find the equation of the circle given center at (5,2) and radius 6√6?

1 Answer

Shwetank Mauria

Jul 16, 2016

Equation of circle is
#x^2+y^2-10x-4y-187=0#

Explanation:

Let #(x,y)# be a point on circle. As it's distance from center #(5,2)# is equal to radius which is #6sqrt6#, hence

#sqrt((x-5)^2+(y-2)^2)=6sqrt6# or

#(x-5)^2+(y-2)^2)=(6sqrt6)^2# or

#x^2-10x+25+y^2-4y+4=36×6# or

#x^2+y^2-10x-4y+25+4-216=0# or

#x^2+y^2-10x-4y-187=0#

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