How do you find the equation for the circle centered at (0,0) that passes through the point (1,-6)?

1 Answer
Mia
Sep 29, 2016

#x^2+y^2=37#

Explanation:

The equation of a circle of center(a,b) and radius r is :
#(x-a)^2+(y-b)^2=r^2#

So,to think about the equation of a circle we should think about its center and radius .

The center is given (0,0).
The circle passes through the point (1,-6) so ,
the radius is the distance between (0,0) and (1,-6)

#r^2=(1-0)^2+(-6-0)^2#
#r^2=1+36=37#

Equation of a circle is:

#(x-0)^2+(y-0)^2=37#
#x^2+y^2=37#

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