How do you find the domain of $y = \sqrt{x^{2} + 4}$ $y=sqrt(x^2+4)$ ?

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Answer 1 · 2016-07-25T08:29:04

Domain: the set of all real numbers

All values of x may be used in the equation whether it be negative, zero , or positive

How do you find the domain of y=√x2+4y=sqrt(x^2+4)?