How do you find the domain of $y =-sqrt(x+1 )-6$ ?

Question

1462 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-28T21:51:14

Assuming that y is restricted to a real number, ( $y in RR$ ), then the argument for the square root must be greater than or equal to 0:

$x + 1 >=0$

$x >=-1 larr$ This is the domain

How do you find the domain of y =-sqrt(x+1 )-6y =-sqrt(x+1 )-6?